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Topic: Introduction to calculas - Limits
Replies: 8   Last Post: Dec 1, 2004 8:34 PM

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Jason

Posts: 31
Registered: 12/6/04
Introduction to calculas - Limits
Posted: Mar 29, 2004 10:35 AM
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I have just started learning calculas and need a few tips.

Q1

lim 4x^2 -36
x app 3 -------- (x approaches 3)
x - 3

= (4 x (3)^2) - 36
----------------
3 - 3

= (4 x 9) - 36
------------
0

= 36 - 36
--------- Book answer = 24
0

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