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Jason
Posts:
31
Registered:
12/6/04


Introduction to calculas  Limits
Posted:
Mar 29, 2004 10:35 AM


I have just started learning calculas and need a few tips.
Q1
lim 4x^2 36 x app 3  (x approaches 3) x  3
= (4 x (3)^2)  36  3  3
= (4 x 9)  36  0
= 36  36  Book answer = 24 0
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