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Topic: Equation
Replies: 3   Last Post: Oct 8, 2001 8:15 PM

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 David Petry Posts: 78 Registered: 12/13/04
Re: Equation
Posted: Oct 8, 2001 8:15 PM

Peter L. Montgomery wrote:
>
> In article <fZ7w7.71498\$NT3.7775356@news1.rdc1.ct.home.com>
> "Austin Fuller" <aust182@home.com> writes:

> >What would be a mathematical way to find out if 65 can be created with these
> >numbers :
> >
> >96,3,3,10

>
> First specify which operations are allowed. Do you allow any of
>
> FLOOR(96 - 3*10.3) = FLOOR(96 - 30.9) = FLOOR(65.1) = 65
>
> 96/3! + SQUARE(10 - 3) = 96/6 + 7^2 = 16 + 49 = 65
>
> 96/FLOOR(SQRT(10)) + 33 = 96/3 + 33 = 32 + 33 = 65
>
> 96 - 3*10 - FLOOR(SQRT(3)) = 96 - 30 - 1 = 65

For that matter, is INVERSE(3) = 1/3 allowed?

96 - 3*(10 + INVERSE(3))

Date Subject Author
10/7/01 Austin Fuller
10/8/01 Peter L. Montgomery
10/8/01 Austin Fuller
10/8/01 David Petry