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Re: Equation
Posted:
Oct 8, 2001 8:15 PM


Peter L. Montgomery wrote: > > In article <fZ7w7.71498$NT3.7775356@news1.rdc1.ct.home.com> > "Austin Fuller" <aust182@home.com> writes: > >What would be a mathematical way to find out if 65 can be created with these > >numbers : > > > >96,3,3,10 > > First specify which operations are allowed. Do you allow any of > > FLOOR(96  3*10.3) = FLOOR(96  30.9) = FLOOR(65.1) = 65 > > 96/3! + SQUARE(10  3) = 96/6 + 7^2 = 16 + 49 = 65 > > 96/FLOOR(SQRT(10)) + 33 = 96/3 + 33 = 32 + 33 = 65 > > 96  3*10  FLOOR(SQRT(3)) = 96  30  1 = 65
For that matter, is INVERSE(3) = 1/3 allowed?
96  3*(10 + INVERSE(3))



