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[mathlearn] ndimensional generalization of p(x,y)  Doctorow
Posted:
Jan 28, 2001 9:15 AM


From: Osher Doctorow, Ph.D. osher@ix.netcom.com, Sunday Jan. 21, 2001, 6:27AM
The function p(x,y,z) of my previous contribution should have been [(1 + y  x) + (1 + y  z)]/2. In general, p(x1, x2, ..., xn) = 1 + y + ... + Sn where Sn = (x1 + x2 + ... + xn)/n where y < = Sn. For the case Sn = x1 = x, which has n = 1, this reduces to p(x,y).
Osher Doctorow Ventura College, West Los Angeles College, etc.
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