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Math Forum » Discussions » sci.math.* » sci.math.independent

Topic: "Logic puzzle" logic
Replies: 15   Last Post: Dec 11, 1999 6:57 PM

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Quentin Grady

Posts: 291
Registered: 12/6/04
Re: "Logic puzzle" logic
Posted: Dec 1, 1999 6:28 PM
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On Wed, 01 Dec 1999 16:39:02 -0400, Gus Gassmann
<Horand.Gassmann@dal.ca> wrote:

>1. Since (L,200) = 1 and (G,200) = 1, (L,G) must be 1.
>
>2. Since (L,G) = 1 and (L,F) = 0, (F,G) = F(200) = 0.
>
>3. Therefore (C,F) = 1, and also (G,N) = 1.

Etc.

Thanks Gus,

It is fabulous to have a second desription. One visual like
Karnaugh maps and the other Boolean algebra. It is all coming
together nicely. I wonder what other surprises you solution oriented
people can throw at it.

Thanks again Gus.







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