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Re: ln(x^x)
Posted:
May 9, 2000 4:12 PM
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>> >I agree - of course ln(x^x) HAS an integral. >> > >> Does it have an integral for x<0 ? >> > >First define it for x<0.
As long as we're at it, we could delve into complex analysis. The ln() function (assuming the principle branch) is defined for all non-zero complex values. Since z^z is non-zero for all non-zero z, we have ln(z^z) = zln(z) defined for C \ {0}. Unfortunately, this function is discontinuous for all z on the line x <= 0, just as ln(z) is.
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