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Topic: ln(x^x)
Replies: 22   Last Post: May 10, 2000 5:27 PM

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Jonathan Hoyle

Posts: 398
Registered: 12/10/04
Re: ln(x^x)
Posted: May 9, 2000 5:16 PM
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>> Since z^z is non-zero for all non-zero z, we have ln(z^z) = zln(z)
>> defined for C \ {0}.

I just realized that this is not true. Duh. :-)

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