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Topic:
ln(x^x)
Replies:
22
Last Post:
May 10, 2000 5:27 PM
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Re: ln(x^x)
Posted:
May 9, 2000 5:16 PM
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>> Since z^z is non-zero for all non-zero z, we have ln(z^z) = zln(z)
>> defined for C \ {0}.
I just realized that this is not true. Duh. :-)
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