
Re: Cardinalities
Posted:
Jun 13, 2000 5:39 AM


In article <20000612220438.28970.00002764@ngfv1.aol.com>, mattalba@aol.comnospam (Matt Albaugh) wrote:
> Theres an easier proof that card(P(N))=card(R): > > card(P(N))=2^card(N) since for all sets "S" card(P(S))=2^card(S) > > card(R)=2^card(N) >
How did you get that last step? You seem to have replaced card(P(N)) with card(R). But that's exactly the thing we're required to prove, so we can't use it.
> Therefore, by equality, card(P(N))=card(R) > > QED. > Matt > > http://www.wam.umd.edu/~mattalba

