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Trisecting an Angle

Date: 11/21/96 at 12:45:13
From: Tracy J Henson
Subject: Trisecting an angel

I've recently been pondering the possibility of trisecting an angle.  
I wasn't sure if it was possible and found a FAQ submitted to you that
stated it was indeed impossible.  Has it been proved to be impossible 
or is it that no one has proved it possible?  The reason I ask is that 
I think (but am not sure) that  I have found a way to trisect an 
angle.  I am a seventh grade math teacher, so I am not completely 
ignorant of mathematical proofs.  I would appreciate some information 
on who would be the best person to contact with my "proof".  I hope 
you believe me because I think this actually works.    

Date: 11/21/96 at 14:47:32
From: Doctor Tom
Subject: Re: Trisecting an angel

Hi Tracy,

There is, in fact, a proof that a trisection is impossible. Many 
people think they have found trisections, but they either don't 
understand exactly what the problem is or their method is flawed.

The problem requires the construction of the trisection using an 
(unmarked) straightedge and a compass. If, for example, you were 
allowed to make 2 marks on the straight-edge, there is a trisection.  
The straight-edge can only connect points already constructed, or use 
arbitrary points, and the compass can only be used similarly.

An exact trisection in a finite number of steps is also required since
it's easy to do a trisection that doesn't require too much accuracy.  
As a limiting case, it might be possible to perfectly trisect an angle 
in an infinite number of steps.

The proof that it's impossible basically considers the arithmetic form 
of the points that can be obtained using a compass and straight-edge.  
In a sense, they are "quadratic" devices - the new points generated 
are solutions of quadratic equations of previously constructed points.

So you can clearly get things like square roots, fourth roots, eighth 
roots, and so on (and it's a bit more complicated than that - what 
you can get are field extensions of degree 2 over whatever you begin 
with). But you CANNOT solve irreducible cubic equations this way - 
such solutions require extensions of degree 3, and no combination of 
multiples of 2 gives a multiple of 3 (to put it in an inexact, but 
hopefully clear, way).

You can, beginning from nothing, construct a 60 degree angle. So if 
you can trisect anything, you can trisect the 60 degree angle which 
you produce. So if you have a trisection, you can construct, from 
scratch, a 20 degree angle. Hence you can construct the sine and 
cosine of 20 degrees.  But it's easy to show that the sine and cosine 
of 20 degrees are roots of an irreducible cubic equation over the 
rational numbers.  This is a contradiction, so a trisection is 

To get the details, read about fields and field extensions in an 
abstract algebra book.  Also, to find out more about trisecting angles 
(or not being able to do so!), do a search under "trisecting an angle" 

or take a look at this site:   

So the bottom line is, there's probably something wrong with your
trisection, not because I've seen it, but because I've studied field 
extensions and irreducibility.

(And I'm not sure about trisecting "angels" as in your title - you'll 
need to talk to a Bible expert about that :^)

-Doctor Tom,  The Math Forum
 Check out our web site!   

Date: 11/21/96 at 22:36:25
From: Tracy J Henson
Subject: Re: Trisecting an angel

Thanks for  your swift response.  I thought I found all the typos.  
I surely would never attempt to trisect or even bisect an angel.

Associated Topics:
College Constructions
High School Constructions

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