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Folium of Descartes and Parametric EquationsDate: 11/23/98 at 01:12:20 From: Benjamin Goh Subject: Plotting an implicit function (e.g. y^3 + x^3 = 3xy) I have a mathematics dictionary at home, and I've come across a strange looking graph, called the folium of Descartes, with an equation of y^3 + x^3 = 3xy. After thinking about it, I realized that I can't simply create a table of x and y values to plot this curve, since I cannot make either y or x the subject of the equation. Many graph programs also are unable to plot this graph (Graphmatica, Equation Grapher. . .) I've found one way to plot such a graph, and that is testing every point on an x-y plane to see if it roughly fits the equation, but this method is rather slow. Is there another, better way to plot such implicit graphs? They are much more interesting than standard ones. I've been experimenting, and one of my favourites is tan(x^3) + log(sin(y^2)) = 3sin(x)cos(y). It has a very interesting pattern, but it's quite hard to plot.
Date: 11/23/98 at 08:57:01
From: Doctor Jerry
Subject: Re: Plotting an implicit function (e.g. y^3 + x^3 = 3xy)
Hi Benjamin,
Some equations can be described with parametric equations. It happens
that the folium of Descartes can be so described.
The equation x^3 + y^3 = 3*a*x*y is equivalent to:
x = 3*a*t/(1+t^3)
y = 3*a*t^2/(1+t^3)
You can plot this by taking several values of t, calculating the x and
y values, and plotting (x,y). I've plotted above equations using the
Mathematica command:
ParametricPlot[{3*t/(1+t^3),3*t^2/(1+t^3)},{t,-100,100},
PlotRange->{-1.5,2}]
to get a rough sketch:
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