Area of an Ellipse Cut by a ChordDate: 05/26/2000 at 14:21:46 From: Andy Jordan Subject: Partial Area of an Ellipse Hi, I have been learning partial flow in pipes of different shapes in an upper level civil engineering class. To try to prove my math skills I have taken on the task of trying to figure out partial flow in an elliptical pipe. What I need to know is how you can calculate the area of part of the ellipse, if you know the major and minor axes, and you know the depth of the water, y. Note that the water has to sit on the bottom of the pipe due to gravity, so it's not just floating in the middle. I think if there is a formula, it will vary depending whether the major axis is horizontal or vertical. I know the area of an ellipse is pi*a*b, and I know that you can take the whole area of the ellipse and subtract the percentage of the pipe that isn't being used. But I don't know how to get that percentage or the area of the water. Thanks for the help. Sincerely, Andy Date: 05/26/2000 at 22:46:07 From: Doctor Peterson Subject: Re: Partial Area of an Ellipse Hi, Andy. I'll just give you the basic idea behind the surprisingly simple solution, and let you see how well you can carry it out. An ellipse is just a "stretched" (or "squashed") circle; that is, you can make an ellipse with semiaxes a and b by taking a circle with radius a and multiplying all y coordinates by b/a. When you stretch a figure that way, you multiply all areas by b/a; that's why the formula for area of a whole ellipse is: A = pi a^2 * b/a = pi a b Now, if you just have a segment of an ellipse, you can undo this stretching and get a segment of a circle: ***********+* ****......|b....\**** *..........|......\ * *-----------+-------\---* *.....a....|........\ * ****......|......***+ ************* ********* ***....|....+** **.......|.....\ ** *.........|a....\ * *..........|......\ * *...........|......\ * *-----------+-------\---* *.....a.....|........\ * *..........|........\ * *.........|.........+ **.......|.......** ***....|....*** ********* It will be easiest if the segment is cut parallel to one of the axes, which is likely in your problem according to the way you stated it, but I've shown the harder case, which can be done with just a little more trouble, in case you're allowing the pipe to be tilted. (You'll have to tilt my pictures, of course.) So you can take the dimensions of your elliptical segment, find the corresponding segment of a circle and work out its area, then multiply by b/a. You can either look up the formula for a segment of a circle in our FAQ (click on Formulas), or draw two radii and add the areas of the sector and the triangle that you form. Let me know if you need more help. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
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