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### A Triangle in a Circle

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Date: 05/26/2000 at 20:45:27
From: Simon Gamache
Subject: A triangle in a circle

Hi Dr. Math,

This problem was given to me by my math teacher, and I think I got the
solution, but I'm not sure. Could you confirm my reasoning?

The problem: Suppose you have a circle, and you randomly place two
points on the circumference (points A and B). What is the probability
that a third point called C placed randomly on the circumference of
the circle will form a triangle that will contain the center of the
circle?

I found the following solution:

n
Probability = ---
360

where n: the arc formed by points A and B (in degrees)

Indeed, suppose points A and B form a 60-degree arc. Then point C must
be placed on the 60-degree arc opposite to the arc formed by points A
and B in order to contain the center of the circle. (A picture speaks
1000 words.) And we all know that there are 360 degrees in a circle.
Is there anything wrong with my solution?
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Date: 05/27/2000 at 03:28:37
From: Doctor Mike
Subject: Re: A triangle in a circle

Hi Simon,

Essentially you have it right, but you need to be a little more
careful in stating your solution. When you say "the arc formed...", it
is clear to me from what you have written afterward that you really
mean "the smaller arc formed..." Always state a result precisely.

Also, the special case where points A and B are diametrically opposed
(at opposite ends of a diameter line) is an interesting special case.
The probability in this case depends on exactly what you mean by
"contains the center" above. That is, does a triangle contain the
center if the center is ON one of the legs of the triangle? Or does
the center have to be IN the interior of the triangle? Maybe you
should ask the teacher what was meant.

I agree with what you have written above the "point C must be..." but
I do not agree that you have clearly presented the reasons why this is
true. You leave a bit too much to the imagination and creativity of
the person you are talking/writing to.

I agree that a picture is worth 1000 words in this case, but a clear
and complete proof of your result needs to have a few more words from
you. It's fine to use an example like 60 degrees to give the reader of
your logical argument some help in understanding what you are saying.
You could even say to imagine this 60-degree arc on a clock face from
five o'clock to seven o'clock, but your words must be organized and
clear enough to convince another person that your formula or theorem
is true in ALL cases, not just for the one example given. The ability
to present a logical argument is something that takes practice, and it
will improve with practice.

Here is what I would use. Draw a circle and locate 2 arbitrary points
A and B on the circle. Draw a diameter line from A through the center
to the diametrically opposite point A'. Do the same from B to B'. Now,
I believe it truly is clear from the picture that the third point C
must be located on the smaller arc between A' and B' for triangle ABC
to contain the circle center.

Now let's look at what parts of the circle's circumference we have:

(1) The smaller arc between A and B which you say is n degrees
(2) The smaller arc between B and A'
(3) The smaller arc between A and B'
(4) The smaller arc between A' and B', which is where the C point
must lie for the triangle to contain the circle center.

How do can we be *100 percent sure* that that arc (4) is n degrees? I
would point out that the arcs (1) and (2) together form precisely half
a circle since they are on one side of a diameter line. So since (1)
is n degrees, then (2) must be 180-n degrees. Similarly, arc (3) is
180-n degrees as well. Adding these up, the first 3 arcs together have
(180-n)+(n)+(180-n) = 360-n degrees, and from this it is clear that
arc (4) is n degrees. Do you see how what I have said really forces
the reader to understand that the opposite arc also has n degrees?
(The reader does not have the responsibility to think up a reason for
that fact.) Now, the ending of the proof proceeds as you have done it.

You did well to discover the correct formula for the probability and
to write down your reasons. I just want you to know what a
mathematician must do to really nail down the truth of a theorem
beyond a shadow of a doubt. I hope this helps. Thanks for writing.

- Doctor Mike, The Math Forum
http://mathforum.org/dr.math/
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Associated Topics:
College Euclidean Geometry
College Probability
High School Euclidean/Plane Geometry
High School Probability

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