Expected lifetime in an Exponential DistributionDate: 10/28/1999 at 07:11:16 From: Kevin Williams Subject: Exponential distribution The lifetime X of an electronic component has an exponential distribution such that P(X <= 1000) = 0.75. What is the expected lifetime of the component? Date: 10/28/1999 at 09:35:28 From: Doctor Mitteldorf Subject: Re: Exponential distribution Dear Kevin, They're telling you that the probability has an exponential form. What does that mean? P(x) proportional to exp(-ax) seems to be the logical interpretation. Then we could figure out a from the specification that P(x) = 0.75. But even this is a bit ambiguous. How do weinterpret P(x)? Does it mean, for example, that the probability that the part lasts 1000 hrs or less is proportional to exp(-ax)? Well, it can't mean that. Obviously, the probability that it lasts (1000 hours or less) is GREATER THAN the probability that it lasts (500 hours or less), because the former subsumes the latter. The sensible way to interpret the equation is that the probability of the part failing at any given moment time = x is proportional to exp(-ax). The reason that the probability goes DOWN with increasing time is that there are fewer and fewer parts left operational that have an opportunity to fail as the time grows longer. So we'll interpret the question to mean the only thing it can mean sensibly: that the probability of failure at any moment time = x is proportional to exp(-ax). How do we find a? Well, before we can even think about that, we need to find the constant of proportionality. We can do that by saying that the probability of failure for all times 0 to infinity must add up to 1. Therefore, if p(x) = C*exp(-ax), we can evaluate C by demanding that the integral of p(x) from 0 to infinity should equal 1. Do this first. Solve for C. The next step is to find a. You can do this, now that you know the constant of proportionality, by taking another integral, and setting that integral = 0.75. What integral is that? Now that you know a, you can take the final step, and calculate the mean failure time. That is the same as the expected lifetime. To calculate the expected lifetime, we take the integral x*p(x), again from x = 0 to x = infinity. This is like saying: take a weighted average of all the times that it could fail (x), using the probabilities associated with those times (P(x)) as the weights. That's a lot of steps. Let me know if you get stuck anywhere along the way; and if not, will you write back and let me know what you got for an answer? - Doctor Mitteldorf, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/