Perfect NumbersDate: 11/10/97 at 12:57:26 From: Juan Maria Moreno Subject: Perfect numbers I have found that the sums of the digits of perfect numbers greater than 6 always equal 1. 28 2+8 = 10 = 1 496 4+9+6 = 19 = 10 = 1 33,550,336 3+3+5+5+0+3+3+6 = 28 = 10 = 1 Do the sums of all the digits of perfect numbers equal 1? 33,550,336 returns 28. Will the next perfect number after 33,550,336 return 496? Thanks. Date: 11/10/97 at 14:02:43 From: Doctor Rob Subject: Re: Perfect numbers Yes, when you add the digits of any perfect number bigger than 6, then add the digits of that number, and so on, you eventually get 1. This is because when you divide such a number by 9, it leaves a remainder of 1. This is because prime numbers larger than 2 are always odd, and all even perfect numbers have the form n = 2^(p-1)*(2^p - 1) for a prime p. Since p > 2 is odd, p-1 is even, and so k = (p-1)/2 is an integer. Then the first factor has the form 3*a + 1, because it has the form 2^(p-1) = 4^k = (1 + 3)^k, = 1 + 3*C(k,1) + 3^2*C(k,2) + 3^3*C(k,3) + ... + 3^k* C(k,k), = 1 + 3*a. The second factor is 2^p - 1 = 2*(4^k) - 1, = 2 + 6*a - 1, = 1 + 3*(2*a). Multiply them together, and you get n = (1+3*a)*(1+6*a), = 1 + 9*a + 18*a^2, = 1 + 9*(a+2*a^2), = 1 + 9*b. The sum of the digits of n differs from n by a multiple of 9 because (10^e)*d = (10^e-1)*d + d = 999...999*d + d = 9*(111...111*d) + d. This disposes of all even perfect numbers > 6. There are no known odd perfect numbers, and it is conjectured that none exists, although nobody has yet proven that. If one exists, it has more than 100 digits and has a very complicated prime power factorization. You omitted 8128 = 2^6*127 from your list. The digital sum is 19, whose sum is 10, whose sum is 1. The next perfect number bigger than 33,550,336 is 8,589,869,056, whose sum is 64, whose sum is 10, whose sum is 1. After that is 137438691328, whose sum is 55, whose sum is 10, whose sum is 1. I do not know if there is a perfect number whose digital sum is 496, but it would have to have at least 56, and probably about 110 decimal digits. -Doctor Rob, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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