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Grocery Store Statistics
Date: 06/10/98 at 21:39:03
From: David Delight
Subject: Grocery store statistics
The manager of a grocery store chain is concerned about the quality of
service, as measured by service times. A sample of service times from
two stores is given below.
Store 1 Store 2
x1 (barred) = 12 min x2(barred) = 10 min
S1^2 = 1.9 min S2^2 = 2.5 min
N1 = 7 N2 = 10
1. Develop a 90% confidence interval on the population variance for
the service times for store 1.
2. Develop a 95% confidence interval on the population for the service
times for store 2.
3. Test to determine if there is a difference between the service time
variances for the two stores.
4. Test to determine if the variance times for store 2 is greater than
the variance times for store 1.
Date: 06/11/98 at 12:38:25
From: Doctor Anthony
Subject: Re: Grocery store statistics
There is some doubt about the information you provide. You quote S1^2
as 1.9 min, but if you mean variance then the units are min^2. I shall
be assuming you do mean the variance is 1.9, but if it should be the
standard deviation, then you will have to rework the problem making
the necessary adjustments. I shall be using X^2 to mean chi-squared,
and s^2 to be population variance.
Problem 1:
To find a 90% confidence interval for population variance use the
chi-squared distribution as follows:
We use the inequality:
(N1-1)*S1^2 (N1-1)*S1^2
----------- < s^2 < -----------
X^2(5%) X^2(95%)
In this case the degrees of freedom for X^2 is equal to (N1-1). Then:
6 (1.9) 6 (1.9)
------- < s^2 < -------
12.59 1.64
.9055 < s^2 < 6.95
Problem 2:
Here, degrees of freedom = 10 - 1 = 9.
(N2-1)S2^2 (N2-1)S2^2
---------- < s^2 < ----------
X^2(2.5%) X^2(97.5%)
9 (2.5) 9 (2.5)
------- < s^2 < -------
19.02 2.7
1.183 < s^2 < 8.333
Problem 3:
This problem is similar to question (4) below, except that we do a
two-tailed test rather than a one-tailed test. For this we use F
ratio test:
larger s^2 2.5
F = ----------- = --- = 1.316
smaller s^2 1.9
The degrees of freedom are 9 and 6 so we test our value 1.316 against
the tabular value F(2.5%)(9,6) = 4.83.
Our value of 1.316 is therefore not significant and there is no
evidence of a difference in variance at the 5% level of significance.
[Note that we used F(2.5%) here instead of F(5%) as in question (4).
In other words we have 2.5% in each tail giving a total 5% tail area.]
Problem 4:
Again, for this we use F ratio test.
larger s^2 2.5
F = ----------- = --- = 1.316
smaller s^2 1.9
The degrees of freedom are 9 and 6 so we test our value 1.316 against
the tabular value F(5%)(9,6) = 4.10.
The value 1.316 is clearly not significant and we conclude that the
variance of store 2 is not necessarily greater than store 1.
-Doctor Anthony, The Math Forum
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