Mixing Milk and ButterfatDate: 09/04/2001 at 11:27:17 From: Nicky Subject: Word problem Milk that has 5% butterfat is mixed with milk that has 2% butterfat. How much of each is needed to obtain 60 gallons of milk that has 3% butterfat? This is what I did. X = gallons 5% butterfat Y = " 2% Butterfat X+Y = 60 5%X + 2%Y = 3%(60) I really don't know. Date: 09/04/2001 at 12:45:38 From: Doctor Peterson Subject: Re: Word problem Hi, Nicky. You have made the right first steps. Now you can rewrite the percentages as decimals: 0.05x + 0.02y = 0.03*60 = 1.8 You might like to avoid decimals by multiplying the whole equation by 100: 5x + 2y = 180 Now you have a system of simultaneous equations: x + y = 60 5x + 2y = 180 You have probably learned some method of solving this. If not, the easiest way is to solve the first equation for y: y = 60 - x and then replace y in the second equation with (60-x). This gives you a single equation to solve to find x. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ Date: 09/04/2001 at 13:30:20 From: Doctor Greenie Subject: Re: Word problem Hi, Nicky - You have made a perfectly good start on this problem.... .. you have clearly defined your variables X and Y .. you have correctly written the equation, which says the total amount of milk is 60 gallons: "X gallons with 5% butterfat, plus Y gallons with 2% butterfat, results in a total of 60 gallons" .. you have correctly written the equation describing the amount of butterfat in the mixture: "X gallons with 5% butterfat, plus Y gallons with 2% butterfat, results in 60 gallons with 3% butterfat" For the traditional approach to the mixture problem, you now just need to solve these two equations simultaneously to find the values of X and Y. The immediate difficulty is with that second equation - it is very awkward to try to work with equations containing "%" signs. So let's first change those percents to decimals in your second equation: .05X + .02Y = .03(60) = 1.80 = 1.8 Then your two equations are X + Y = 60 .05X + .02Y = 1.8 For me, at this point, the "ugly" part about this problem is the decimals; so I'm going to multiply the second equation by 100 to get rid of those decimals: X + Y = 60 5X + 2Y = 180 Now you can use your favorite method to solve these two equations; for me, with these two equations, a linear combination method looks easy to use... 5X + 2Y = 180 2X + 2Y = 120 --------------- 3X = 60 So I have X = 20 from which it follows that Y = 40 So the mixture needs to be 20 gallons of milk with 5% butterfat and 40 gallons of milk with 2% butterfat. The preceding is the traditional approach to solving mixture problems; it is the method I have always seen taught. Following below is the solution to this same problem using an alternative approach that I find is usually far easier to use. This alternative approach uses the idea that the relative closeness of the desired percentage for the mixture to the percentages of the two given batches determines the fraction of the mixture that is to be made up of each of the two batches. For example, if a "mixture" is made using only batch A, the "mixture" will have the same percentage as batch A. If a mixture is made using equal parts of batch A and batch B, the mixture will have a percentage halfway between the percentages of batches A and B. And if a mixture is made using 3 parts of batch A and 1 part of batch B, then the percentage of that mixture will be 3 times as close to the percentage of batch A as it is to the percentage of batch B. So...... Here is what you are given: The two batches of milk being mixed contain 2% butterfat and 5% butterfat; the desired mixture is to contain 3% butterfat. Here is the reasoning you use to find what fraction of the mixture should be from each of the two given batches: 1) Think of 2%, 3%, and 5% on a number line. The "distance" from 2% to 3% is 1%; the "distance" from 3% to 5% is 2%. 2) The desired percentage of butterfat is twice as close to 2% as it is to 5%. 3) Therefore, the mixture should contain two parts of the 2% batch for every one part of the 5% batch. 4) This means the ratio of the amount of the 2% batch to the amount of the 5% batch should be 2:1. 5) This in turn means that 2/3 of the mixture should be the 2% batch and 1/3 of the mixture should be the 5% batch. 6) Finally, with the mixture being 60 gallons, this means that the mixture should contain (2/3)x60 = 40 gallons of the batch with 2% butterfat and (1/3)x60 = 20 gallons of the batch with 5% butterfat. I hope this helps. Write back if you have any further questions about this type of problem. - Doctor Greenie, The Math Forum http://mathforum.org/dr.math/ |
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