Regrouping PolynomialsDate: 11/26/2001 at 01:39:19 From: jessica Subject: Elementary algebra I'm stuck on how to do the regrouping of polynomials. The problem is: a^2x - bx - a^2y + by + a^2z - bz Please help. Thank you. Jess Date: 11/26/2001 at 10:12:04 From: Doctor Ian Subject: Re: Elementary algebra Hi Jessica, The basic idea in regrouping is to look for opportunities to apply the distributive property: this*bibbity + this*bobbity + ... + this*boo = this(bibbibty + bobbity + ... + boo) Sometimes applying it once is enough; sometimes you have to apply it several times. That's the case with a^2x - bx - a^2y + by + a^2z - bz We might begin by noticing that the coefficients a^2 and b are shared by several terms, so we can group those together and distribute the multiplications: a^2x - bx - a^2y + by + a^2z - bz = a^2x - a^2y + a^2z - bx + by - bz = a^2(x - y + z) - b(x - y + z) = (a^2 - b)(x - y + z) On the other hand, we might concentrate on the variables x and y instead: a^2x - bx - a^2y + by + a^2z - bz = (a^2 - b)x - (a^2 - b)y + (a^2 - b)z = (a^2 - b)(x - y + z) Either way, we end up with the same thing. What makes this problem tricky is that it has lots of minus signs. If you find minus signs confusing, you can try changing '- something' to '+ (-1)something' wherever it occurs. Then you only have to deal with additions: a^2x - bx - a^2y + by + a^2z - bz = a^2x + (-1)bx + (-1)a^2y + by + a^2z + (-1)bz = a^2(x + (-1)y + z) + b((-1)x + y + (-1)z) = a^2(x - y + z) + b(-x + y - z) Note that in this form, you can't use the distributive property a second time. So it's useful to know that you can distribute a -1 across a sum by changing all the signs. For example, (-1)(-x + y - z) = ((-1)(-x) + (-1)y + (-1)(-z)) = (x - y + z) So we can use this trick to change (-x + y - z) to (x - y + z), by subtracting the one instead of adding the other: = a^2(x - y + z) + b(-x + y - z) = a^2(x - y + z) - b( x - y + z) = (a^2 - b)(x - y + z) Once you get enough practice, switching the signs will seem like a very natural thing. But until then, it's probably best to write all the steps out explicitly, e.g., = a^2(x - y + z) + b(-x + y - z) = a^2(x - y + z) - (-1)b(-x + y - z) \_______________/ b(-1)(-x + y - z) \_______________/ b((-1)(-x) + (-1)(y) - (-1)(z)) \_____________________________/ b(x - y + z) = a^2(x - y + z) - b(x - y + z) This trick (switching signs by subtracting instead of adding) turns out to be useful in lots of simplification problems. One place to look for it is when trying to cancel common expressions in the numerator and denominator of a fraction, e.g., -x - y (-1)x + (-1)y (-1)(x + y) ------ = ------------- = ----------- = -1 x + y x + y x + y Does this help? - Doctor Ian, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/