ParityDate: 8/2/96 at 1:58:23 From: Alfred T Chu Subject: Parity Dear Dr. Math, How do I determine if the following function is odd, even or neither? What is the symmetry of the graph? 4 2 -1 k(x)= (x + x +1) Thanks! I hope you understand my problem and how I typed it. Sincerely, Alfred Date: 8/6/96 at 10:56:53 From: Doctor Jerry Subject: Re: Parity Dear Alfred, The function k(x) = (x^4+x^2+1)^(-1) is an even function since k(x) = k(-x) for all x. This means the graph is symmetric about the y-axis. If, for example, (a,b) is on the graph, then so is (-a,b). Why? Well, if (a,b) is on the graph, then b=k(a). But, b=k(a)=k(-a). So, (-a,b) is on the graph. -Doctor Jerry, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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