Solving Linear Inequalities with Absolute ValuesDate: 05/31/98 at 18:09:29 From: Carolyn Subject: Linear inequalities I have two questions that I am having difficulty solving. 1) 3 <= |x + 2| < 8 I have broken it into two parts: (a) |x + 2| < 8 and (b) |x + 2| >= 3 From that, I have gotten for (a) |x| < 6 or |x| < -10 and for (b) |x| >= 1 or |x| >= -5. Now, how do I put that on the line, or is there more I have to do? 2) 3 < |2x + 1| or |x + 1| - 3 > 2 I have done this so far: 2 + 3 < |x + 1|, which means 5 < |x + 1|. I'm lost at this point. Date: 05/31/98 at 23:27:48 From: Doctor Pat Subject: Re: Linear inequalities Carolyn, I'm going to try to help you see a new way to approach these, rather than just correct the mistakes above. It seems like you're trying to plow through this with some memorized algebra techniques without really understanding the idea, which for me is the most important part, so let's try to find a way to "see" the answer, then work from there. Let's look at the whole first problem: 3 <= |x + 2| < 8. We are looking for some numbers on the number line so that when we put them into the equation, the whole thing is true. Draw a number line and mark off x values in increments of, say, five or so, like this -10 -5 0 5 10 15 20 ____|___|___|___|___|___|___|___|___ Now, let's get an idea about which neighborhood would be the one we want. We take all these numbers, add two, then write the absolute value like this: -10 -5 0 5 10 15 20 ____|___|___|___|___|___|___|___|___ 8 3 2 7 12 17 22 Which numbers are between three and eight? Well, by luck we see that numbers from -10 to -5 seem to work. It also looks like we should find another set of numbers just a little to the right of the origin (0). We could put more values in the area from 0 to ten and repeat, but I think you see where this is going. Let's look back at the values you have already found: -10, -5, 1, and 6. You found endpoints at all the right places; now, all we have to do is write them out as intervals joined by the "or" statement. Can you look at the number line again and write that out? You want a statement that says "x is between -10 and -5 or else x is between 1 and 6." You need to put in the correct endpoint values to match up the < verses <=, but that is nothing compared to all the work you've already done. I will let you try to draw the picture of the next one. I hope this helps you make sense of absolute values and inequalities. Math is really difficult if you are not even sure when you are doing it right, so try to keep understanding the big ideas, and the rest sort of works out. Good luck and write back if you need more help. -Doctor Pat, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/