Relative DensityDate: 05/18/2000 at 02:01:08 From: Chris Guerra Subject: density Is this physics problem possible? A solid object floats in water with three-fourths of its volume beneath the surface. What is the object's density? Date: 05/18/2000 at 08:55:14 From: Doctor Rick Subject: Re: density Hi, Chris. Yes, the problem can be solved. The floating object displaces a volume of water equal to 3/4 of its own volume. Let's say the volume of the object is V. The volume of displaced water is then (3/4)V. The density of water is 1 gram/cm^3 (a gram was defined so that this would be true). Mass equals density times volume, so you can write an expression for the mass M of the displaced water. The volume of water displaced by a floating object is equal to the mass of the object. Therefore the object also has mass M. The density of the object is defined as M/V. You can do the rest. - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ |
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