Point on a ParabolaDate: 9 Jan 1995 07:14:24 -0500 From: Secret Someone Subject: (none) How do you find the point on the parabola y=x^2 nearest the point (-3,0)??? Thanks, Steven Burris Date: 9 Jan 1995 14:41:30 -0500 From: Dr. Ken Subject: Re: your mail Hey there! I'll see if I can get you started, although I'm not sure how far you've gotten yet. You want to use the distance formula (between the given point and a general point on the parabola), and then minimize the quantity it gives you. So this will be set up as a max-min problem, and you'll take the derivative of the distance, set it equal to zero, blah blah blah. Let us know if this isn't enough to get you going. -Ken "Dr." Math |
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