Date: 22 Feb 1995 17:31:27 -0500 From: Anonymous Subject: Re: math problem Hello there! How do you integrate the function: (tan2x)^3 dx, in terms of x? Thank you, confused with calculus
Date: 22 Feb 1995 17:31:27 -0500 From: Dr. Ken Subject: Re: math problem I'll give you a hint, and if you're still confused, come back and I'll try to explain it in more detail. You've got (Tan2x)^3, which splits into (Tan2x)(Tan2x)^2. Now remember the formula Tan^2 u + 1 = Sec^2 u, and use it to turn your integrand into (Tan2x)((Sec2x)^2 - 1). Distribute the Tan2x to get Tan2x(Sec2x)^2 - Tan2x. Now can you do the problem? -Ken "Dr." Math
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