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Integration by PartsDate: 12/8/95 at 5:12:43 From: "Juergen Meier" Subject: Integration can be difficult Suche Stammfunktion fuer : x^n/e^x
Date: 5/30/96 at 11:16:51
From: Doctor Anthony
Subject: Re: Integration can be difficult
Using integration by parts, it is easy to get a reduction formula,
especially if the range of integration is from 0 to infinity. I
shall assume these limits for the integration
Let I(n) = INT{x^n/e^x.dx} = INT{x^n.e^(-x).dx} (from 0 to infinity)
= x^n(-e^(-x)) + n.INT{x^(n-1).e^(-x).dx} (from 0 to infinity)
= 0 + n.I(n-1) and continuing in this manner
= n(n-1).I(n-2)
Continue this process until, n(n-1)(n-2)...3.2.1.INT{e^(-x).dx}
(0 to inf.)
and this final integral is +1
So the value of the integral is n(n-1)(n-2)...3.2.1 = n!
If the limits are other than 0 to infinity, then there will be no
simple formula for the integral. Provided n is not too large, it
can nevertheless be evaluated quite quickly.
-Doctor Anthony, The Math Forum
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