Rate of Change of a FunctionDate: 6/10/96 at 19:15:55 From: Anonymous Subject: Rate of change I'm stuck on this problem: The rate of change of the function f(x) = sin x + csc x with respect to change in the variable x is given by the expression cos x - csc x cot x. Show that the expression for the rate of change can also be given by -cos x cot^2 x. Date: 6/11/96 at 19:34:35 From: Doctor Anthony Subject: Re: Rate of change dy/dx = cos(x) - (1/sin(x) * cos(x)/sin(x)) = cos(x){1 - 1/sin^2(x)} = cos(x){(sin^2(x)-1)/sin^2(x)} = cos(x){-cos^2(x)/sin^2(x)} = -cos(x)cot^2(x) -Doctor Anthony, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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