Solving a Logarithm
Date: 6/29/96 at 1:10:28 From: Anonymous Subject: Solving a Logarithm Hi! How are you? I need help. Can you help me solve this question? log a = -1.3
Date: 6/30/96 at 15:44:48 From: Doctor Luis Subject: Re: Solving a Logarithm In order to answer this question, you have to understand the definition of a logarithm: log(base p) q = r if and only if p ^ r = q. [read p ^ r as "p raised to r-th power] In other words, the logarithm represents the power to which you need to raise the base to in order to give you the number in front. example: log(base 2) 32 = 5 ( why? because 2 ^ 5 = 32 ) Since you did not specify a base, by default it's 10 (some authors take "e" as the default base) Now you can write log(base 10) a = -1.3 in the equivalent exponential form by using the definition provided above, thus giving you the value of a. -Doctor Luis, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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