Associated Topics || Dr. Math Home || Search Dr. Math

### Ptolemy's Theorem and Double-angle Formulas

```
Date: 7/11/96 at 7:27:42
From: Alan Yu
Subject: Ptolemy Theorem and Double-angle Formulas

Dr. Maths,

Thanks for your previous instructions on how to show the
compound angle formula Sin(A+B)= Sin(A)Cos(B) + Cos(A)Sin(B).  I
followed your steps and found out the proof. Thank you so much for

Is it possible to show the formula Sin(A-B), Cos(A+B) or
Cos(A-B) with Ptolemy's Theorem?

Alan
```

```
Date: 7/11/96 at 12:46:57
From: Doctor Anthony
Subject: Re: Ptolemy Theorem and Double-angle Formulas

Once you have established the formula for sin(A+B), the others can be
derived directly from that.  You need to know that sin(-B) = -sin(B),
cos(-B)=cos(B), sin(pi/2 - A) = cos(A), cos(pi/2 - A) = sin(A).  Then:

sin(A+(-B)) = sin(A)cos(-B) + cos(A)sin(-B)
sin(A-B) = sin(A)cos(B) - cos(A)sin(B)

sin(pi/2 -(A+B)) = sin((pi/2-A) -B)
cos(A+B) = sin(pi/2-A)cos(-B) + cos(pi/2-A)sin(-B)
= cos(A)cos(B) - sin(A)sin(B)

sin(pi/2 -(A-B)) = sin(pi/2-A + B)
cos(A-B) = sin(pi/2-A)cos(B) + cos(pi/2-A)sin(B)
= cos(A)cos(B) + sin(A)sin(B)

-Doctor Anthony,  The Math Forum
Check out our web site!  http://mathforum.org/dr.math/
```
Associated Topics:
High School Calculus

Search the Dr. Math Library:

 Find items containing (put spaces between keywords):   Click only once for faster results: [ Choose "whole words" when searching for a word like age.] all keywords, in any order at least one, that exact phrase parts of words whole words

Submit your own question to Dr. Math
Math Forum Home || Math Library || Quick Reference || Math Forum Search