When i^n Will Be i, -i, or 1
Date: 9/10/96 at 15:57:29 From: Anonymous Subject: When i^n will be i, -i, or 1 Raising "i" to a power runs in cycles. i to the first is i, i to the second is -1, i to the third is -i, and i to the fourth is 1. And then the cycle starts over. I was taught that to find the value of i, no matter the exponent, divide the exponent by 4 and the remainder will be the equivalent exponent to make finding the value of i easier. For example, raise i to the 11th. Now divide 11 by 4, and you get a remainder of 3. Now, i to the 3rd (from the remainder) is -i and that's your answer. Now, My teacher doesn't always like to explain why things like this happen and sometimes gets mad if we do, so I'm asking you. Why does this remainder method work? What's the theory behind it?
Date: 9/10/96 at 19:0:47 From: Doctor Tom Subject: Re: When i^n will be i, -i, or 1 I think you're not far from seeing the answer. Instead of stopping at i^4, let's make a longer list: i -1 -i 1 i -1 -i 1 i -1 -i 1 i -1 -i 1 ... The list above shows i to the first, second, third, ... powers. Notice that it repeats forever, because once you get back to 1, multiplying by the next i starts the pattern over again. So since the pattern is 4 steps long, every set of four steps gets you back to where you were. Going 3 steps is the same as going 7 steps or 11 steps or 15 steps, since each is just 4 more than the previous. Now think about what the "remainder after dividing by 4" means. It means that 4 went in some number of times, and there was some left over. But every time 4 went in, that's just a complete loop in the cycle, so you can ignore it - it brings you back to where you started. The only thing that matters is the remainder. To make it completely clear, look at your example -- i^11. Well, 11 = 2*4 + 3. The quotient is 2, and the remainder is 3. The quotient just says you went completely through the cycle twice, and then there were 3 left over. So it's the same as i^3 = -i. -Doctor Tom, The Math Forum Check out our web site! http://mathforum.org/dr.math/
Date: 9/11/96 at 15:7:22 From: Xavier Subject: Re: When i^n will be i, -i, or 1 Thank you very much Dr. Math! Today, another student asked the teacher the same question I asked you and I explained it better then the teacher, thanks to your help! Ryan
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