Vertices of an OctagonDate: 10/29/96 at 1:20:20 From: K.N.Krishna Murthy Subject: How to compute vertices of an octagon Hello Dr. Math, I am so glad to find a wonderful site for maths questions. I would like to know the answer for the following question: Given an octagon of size 100 millimetres with center at (0,0), how do I find the coordinates of the 8 vertices? Is there a formula? Thank you in advance, Krishna Date: 10/29/96 at 8:16:11 From: Doctor Jerry Subject: Re: How to compute vertices of an octagon Dear Krishna, Imagine a circle of radius 100 mm. We'll calculate the vertices of an octagon as points on this circle. From the definition of the trigonometric functions sine and cosine, if t is an angle in standard position (initial side along the positive x-axis and terminal side t radians counterclockwise from the initial side), then the coordinates of a point on a circle of radius a and with angle t are (a*cos(t), a*sin(t)). With (100,0) as one vertex, the next vertex will be (100*cos(2*pi/8), 100*sin(2*pi/8)), the next will be (100*cos(4*pi/8), 100*sin(4*pi/8)), and so on. All of these simplify quite a bit, since 2*pi/8 = pi/4 and cosine and sine of pi/4 are well known. I hope this is clear. You can see that I've assumed that you know trignonometry. Please write back if necessary. -Doctor Jerry, The Math Forum Check out our web site! http://mathforum.org/dr.math/ Date: 10/30/96 at 6:37:50 From: K N Krishna Murthy Wipro Systems 11901 Subject: Re: How to compute vertices of an octagon Hello Dr. Math, I have another question based on the one you have just answered: I have a square of size 100 millimetres and I want to inscribe an octagon in this square. The center of the square is (0,0). How do I find the coordinates of the vertices of the octagon? Thank you again, Krishna Date: 10/30/96 at 8:31:19 From: Doctor Jerry Subject: Re: How to compute vertices of an OCTAGON Dear Krishna, I'll assume that you want every other side of the octagon to be collinear with the square. Look first at the vertex V1 of the octagon just above the x-axis. The angle between the line from the origin to V1 and the x-axis is pi/8. Using a right triangle, the circle passing through the vertices of the octagon has radius d, where d = 50/cos(pi/8). Now you can easily write down the vertices of the octagon, using a formula similar to the one given earlier: V1 = (d*cos(pi/8),d*sin(pi/8)) V2 = (d*cos(pi/8+1*(pi/4)),d*sin(pi/8+1*(pi/4))) V3 = (d*cos(pi/8+2*(pi/4)),d*sin(pi/8+2*(pi/4))) and so on. -Doctor Jerry, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994- The Math Forum at NCTM. All rights reserved.
http://mathforum.org/dr.math/