Right Triangle Kite ProblemDate: 01/16/97 at 16:09:29 From: Alvin Wilson Subject: How high is the kite? Hello Dr. Math, I am having trouble with a trigometry problem: When flying a kite, 150 ft. makes an an angle of 51 degrees with the ground. Assume the string is straight. How high above the ground is the kite to the nearest tenth of a foot? Thanks, Alvin Wilson Date: 01/16/97 at 18:32:22 From: Doctor Scott Subject: Re: How high is the kite? Hey Alvin!! Great question. It's a good example of a right triangle trigonometry problem. Remember that in a right triangle, ABC, with a right angle at B, A |\ | \ | \ | \ | \ |__________\ B C the sine of angle C is defined to be OPPOSITE / HYPOTENUSE (AB/AC) the cosine of C is define d to be ADJACENT / HYPOTENUSE (BC/AC) the tangent of C is defined to be OPPOSITE / ADJACENT (AB/BC) It's usually a good idea to "zone in" on an angle, then decide what trig ratio to use. So, for your problem, the HYPOTENUSE is the length of kite string (150) and the angle with the ground is at C (51 degrees). So, we are looking for side BA. With the angle in mind, we are trying to FIND the opposite side and we are given the hypotenuse, so we think SINE! So, sin 51 = AB / 150. Using a calculator or table, sin 51 = 0.77714596, so we have 0.77714596 = AB -------------- ----- 1 150 We can solve this by cross multiplying: 150*0.7714596 = AB So, AB = 116.6 (rounded to the nearest tenth) -Doctor Scott, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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