Demonstrating Sin, Cos, Tan on the Unit CircleDate: 12/30/98 at 02:45:08 From: Ally Miller Subject: Demonstrating tan, csc, sec, or cot I am trying to "build a trig function," so to speak. For instance, you can demonstrate cos and sin with a pendulum or a ferris wheel by plotting the various heights a specific point reaches as it goes around its circular path. But how can you demonstrate the other four trig functions? Would a sundial work? I didn't think that you could demonstrate them since all have infinite ranges. Is there any real life example of a tan, csc, sec, or cot function? Thanks. Date: 12/30/98 at 08:18:51 From: Doctor Jerry Subject: Re: Demonstrating tan, csc, sec, or cot Hi Ally, Suppose that you draw or construct a unit circle (radius 1). Starting from the center, draw a horizontal line to the right, from the center O of the circle to a point E on its circumference. Now draw an arbitrary angle t (but 0 < t < 90) by drawing a line from O to a point T on the circumference and then extend OT to a point F directly above E. Finally, draw a line starting from T, directly down to OE at point G, so that TG is perpendicular to OE: Then the distance FE is tan(t), OG is cos(t), and TG is sin(t). One might argue that the other trig functions are just reciprocals of these three and do not need to be explained in the same way. - Doctor Jerry, The Math Forum http://mathforum.org/dr.math/ Date: 12/31/98 at 03:07:05 From: Meatball Head Subject: Re: Demonstrating tan, csc, sec, or cot Thank you very much for the reply, but I just have a quick question. I understand what the diagram should look like, but can you explain to me why this works? Also, how do I show how the tan function changes over an interval of at least 80 degrees? Thanks! -Ally Date: 12/31/98 at 07:44:22 From: Doctor Jerry Subject: Re: Demonstrating tan, csc, sec, or cot Hi Ally, I can explain why it works in the following way. First, in triangle OFE, the angle at E is a right angle. So: tan(t) = side opposite/side adjacent = FE/1 The lengths of OE and OT are 1 since it is a unit circle. In the triangle OTG, the right angle is at G, so: sin(t) = side opposite/hypotenuse = TG/OT = TG Also: cos(t) = side adjacent/hypotenuse = OG/OT = OG This diagram will work as t varies from 0 to 80 or even 85 degrees, although EF becomes quite long. Did you notice that EF is TANGENT to the circle at E? - Doctor Jerry, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/