Connecting the Boxes
Date: 12/28/98 at 01:15:30 From: Danny Subject: Box puzzle |-----|------| | | | | | | |--|--|--|---| | | | | |--|-----|---| This may sound silly, but we have been trying to figure this out for almost a month now. Draw one continuous line crossing every line (including the outside edges) once and only once. You can not trace along the lines you are trying to cross or cross on the same point as a previous line. Many thanks, Danny Mainprize, Brookwood High School
Date: 12/28/98 at 09:53:53 From: Doctor Rob Subject: Re: Box puzzle Thanks for writing to Ask Dr. Math! Sorry, this is impossible. Do not waste any more time trying! The upper two boxes and the middle bottom one each have five line segments that have to be crossed by your curve. Every time you enter and exit a box, the curve crosses two line segments. If you do that twice to each of these three boxes, that will leave one line segment to be crossed in each. To do that, you have to either start or end your curve in that box. But the curve has only two ends, and there are three such boxes. That means that in whichever boxes you start and end the curve, there will be one leftover box with a line segment not crossed. This problem is very similar to a famous one called the Bridges of Koenigsberg, which was solved by Leonhard Euler in the 18th century. Here is a good place to look for information on the history of the Bridges of Koenigsberg: http://mathforum.org/~isaac/problems/bridges1.html - Doctor Rob, The Math Forum http://mathforum.org/dr.math/
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