Absolute Value Equation with Diagonal Axis of Symmetry
Date: 01/10/2002 at 00:58:32 From: Anonymous Subject: Absolute Value Equation with Diagonal Axis of Symmetry What's an example of an absolute value equation where the axis of symmetry is a diagonal line, say y = x?
Date: 01/10/2002 at 09:11:01 From: Doctor Peterson Subject: Re: Absolute Value Equation with Diagonal Axis of Symmetry Hi, That symmetry implies that swapping the roles of x and y in the equation will leave it unchanged. So any equation you can write in which x and y play interchangeable roles will have the desired symmetry. For example, try |x + y| = |x - y| Swapping x and y gives |y + x| = |y - x| which is equivalent. Of course, many such equations you might write will have empty graphs, or otherwise be uninteresting, so the hard part is to choose one that is of interest, and to be able to graph what you get. The one I just suggested is very interesting, though the graph is surprisingly simple. If, say, you multiply the right side by 2, or take off the absolute value sign on the left, it will be even more interesting. Have fun playing with these. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/
Date: 01/10/2002 at 12:58:57 From: Anonymous Subject: Absolute Value Equation with Diagonal Axis of Symmetry I'm still not getting the graphs I want. Basically, I'm looking to graph an absolute value graph where essentially, I'm taking y = |x| and "rotating it" 45 degrees, say to the right (So I now have a V-shaped graph with an "axis of symmetry" of y = x.) As you suggested, how can I get such a graph from graphing |x + y| = |x - y| or |y + x| = |y - x| or, as you suggest, by "multiplying the right side by 2, or taking off the absolute value sign on the left." I'm just not following this. Thanks.
Date: 01/10/2002 at 13:33:18 From: Doctor Peterson Subject: Re: Absolute Value Equation with Diagonal Axis of Symmetry Hi, You didn't say you wanted to actually rotate y=|x|; I took your question to mean you wanted an equation, involving the absolute value, that had the desired symmetry. But in fact, I told you how to do what you want. Try graphing my last suggestion, x + y = |y - x| and see what it looks like. Were you not able to graph the equations I suggested? I'll show you how to graph the first: |x + y| = |x - y| There are four cases, depending on whether each operand is positive or negative. Notice that x+y is positive when y > -x, so you can draw the line y = -x lightly and indicate that above it, x+y>0. Similarly, x-y is positive when y < x, so draw the line y=x lightly and indicate that x-y>0 below it. This divides the plane into four regions. x+y>0, x-y>0: x + y = x - y 2y = 0 y = 0 So darken the x axis within this part of the plane. x+y>0, x-y<0: x + y = y - x 2x = 0 x = 0 So darken the y axis within this part of the plane. The other two regions repeat the same work. You will end up with a graph consisting of the x and y axes. Now do the same with the new equation I suggested above, and compare what you get with y=|x|. There are standard techniques for rotating a graph that depend on replacing the variables with a new set of rotated variables. To rotate any graph, such as y=|x|, 45 degrees to the right, you have to replace x with (x-y)/sqrt(2) and y with (x+y)/sqrt(2) Try doing that with y=|x|, and you will get the equation I suggested. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/
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