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Long First Month Mortgage Payment CalculationDate: 06/22/2001 at 00:15:28 From: Genevieve Chan Subject: Long 1st month mortgage payment calculation Dr. Math, All the mortgage payment formulae seem to deal with level pay whole monthly payments, given interest, loan principal, and length of the loan. But in the real world, if one applies for a loan, the first payment generally is not exactly one month from the time the loan is taken. For example, imagine a loan is taken out on Jan. 15, 2001. The first payment is due Jan. 25, 2001. Thereafter payment is due on the 25th of each month. The principal is 120,000, interest is 8%. The length of the loan is 15 years (180 payments). Can this problem be solved with one formula? If not how would you calculate the monthly payment amount, given that the payments have to be a uniform amount for the entire loan life? That is, the monthly payment amount is the same from payment 1 to 180. Thank you in advance. Regards.
Date: 06/22/2001 at 06:55:07
From: Doctor Mitteldorf
Subject: Re: Long 1st month mortgage payment calculation
Dear Genevieve,
In the real world, most banks and lenders duck this mathematical
problem by treating the first month differently: the borrower gets his
full loan, but then immediately pays back the partial month's interest
in advance. This is called "prepaid interest." The remaining loan is
an even number of payment periods, and is calculated in the standard
way.
The bank actually reaps a small benefit from this practice, because
for the partial month the payment is in advance, whereas any other way
of treating the partial month would follow the standard practice of
charging interest in arrears.
If you want to do the calculation with level payments including the
partial months, it is not any more difficult than the calculation for
an even number of months. The trick is to think in terms of present
values, and to use the principle that
=> the present value of all payments as of the loan date is equal to
the amount of the loan.
Let's take your example. The nominal interest rate is 8%, so the
monthly interest is 8/12 of 1% or 0.006667. So each month, the
present value of your payment is discounted by another factor of
1/(1+0.006667) = 0.993377. For the partial month, there are varying,
slightly different ways to compute the discounting factor; for now,
I'll use the simplest and calculate it as 10/30 of a full month's
interest, so 8/36 of 1% is 0.002222, and 1/(1+0.002222) = 0.997782.
Now let's call the unknown payment amount p. The first payment is made
after 10/30 of a month, so its present value is discounted by the
factor 0.99777. The second payment is discounted by 0.99777*0.993377,
and the third by 0.99778*0.993377*0.993377, the fourth by
0.99777*0.993377*0.993377*0.993377, etc. So the sum of the present
values of the payments is
p*0.99778*(1 + 0.993377 + 0.993377^2 + 0.993377^3 + ... +
0.993377^179)
We can find the sum of the series in parentheses using the same
standard technique we always use. Call the sum S. Multiply S times
0.99333, and notice that the product is almost the same, just missing
the first term and with an extra term tacked on at the end:
S = 1 + 0.993377 + 0.993377^2 + 0.993377^3 + ... +
0.993377^179
0.993378*S = 0.993377 + 0.993377^2 + 0.993377^3 + ... +
0.993377^180
Therefore 0.993378*S = S - 1 + 0.993378^180. Solve this for S to find
S = (1-0.993378^180) / 0.0066225 = 105.338
Going back to our original equation with p, we have
p * 0.997782 * 105.338 = $120,000
and this gives p = $1141.72
The upshot is that we do the same calculation as for a standard
180-payment loan, but that the payment amount is reduced by a factor
of 0.993378/0.997782. The numerator of this factor is the discounting
factor you would have used for a full month; the denominator is the
discounting factor you actually use for the partial month.
Read more about loan calculations at our FAQ page,
Loans and Interest
http://mathforum.org/dr.math/faq/faq.interest.html
and in the High School Interest area of our Dr. Math archives:
http://mathforum.org/dr.math/tocs/interest.high.html
- Doctor Mitteldorf, The Math Forum
http://mathforum.org/dr.math/
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