Measuring Angles Using SteradiansDate: 2/8/96 at 17:35:55 From: "Kathleen M. Scaffidi" Subject: question We are from Divine Savior Holy Angels High School in Milwaukee Wi. It's an all girls, college prep h.s. We came across a problem in one of our math books and we need help. How do you measure a solid angle by using steradians? Your reply would be greatly appreciated. The students from Mrs. Scaffidi's Honors Math III class Thanks so much! Date: 2/14/96 at 10:1:27 From: Doctor Ethan Subject: Re: question Much like radian measure, which is a unitless description of the size of an angle in two dimensions, steradians are a similar measure of 'solid angles' in three dimensions. An angle in radians compares that angle to a complete circle (2*Pi). Similarly, steradians relate solid angles (which you can imagine as cones radiating out from a point) to an angles that subtend an entire sphere (4*Pi). The two are not interchangable, however. But that's not a precise enough definition with which to do calculations. Consider some surface S enclosing a point P. Now imagine a small cone which intersects an area, da, on S. The cone defines the solid angle 'subtended' by that area at point P. By definition, the solid angle is the area da projected on a plane perpendicular to the radius vector from P to the area (R), and divided by the magnitude of R squared (r^2). If dU is the solid angle subtended by da, we therefore have: R * da dU = ------- r^2 where * is being used as the _dot product_ (not multiplication). The expression can be integrated over a region of S to find the total solid angle subtended. / R * da U = | -------- | r^2 / If the angle between R and the vector normal to da is a constant, A, this expression can be simplified to: / da(cos A) U = | -------- | r^2 / I hope you followed my rather crude attempt to draw an integral symbol. Keep up the good work! -Doctor Ethan, The Math Forum |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/