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### Polygon Angles

```
Date: 02/14/97 at 11:20:27
From: Jon, Ryan, and Tony
Subject: Geometry

Yesterday we looked in the archives and found the names of the
polygons with sides 3-50. We would like to know what is the sum of the
measure of the angles in those polygons, or do you have a formula for
figuring that out?
```

```
Date: 02/14/97 at 11:36:56
From: Doctor Tom
Subject: Re: Geometry

The formula is this:

For an n-sided polygon, the number of degrees for the sum of the
internal angles is 180(n-2).

For n=3 (triangle), it's 180.
And so on.

But rather than memorize a formula, it's easier to think about it
this way. A triangle has 180 degrees. If you have a 4-sided figure,
connect 2 vertices forming 2 triangles, and so you have 2*(180)
degrees.  If you cut up a pentagon, you'll get 3 triangles, and
so on.

Draw some pictures and see that each time you add a side, you'll
need one more triangle.  Try it with oddball-shaped figures like
stars and stuff, and see that it still works.

-Doctor Tom,  The Math Forum
Check out our web site!  http://mathforum.org/dr.math/
```
Associated Topics:
High School Euclidean/Plane Geometry
High School Geometry
High School Triangles and Other Polygons
Middle School Geometry
Middle School Triangles and Other Polygons
Middle School Two-Dimensional Geometry

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