Date: 08/26/98 at 22:52:07 From: Todd Subject: Geometry Draw a diagram in which the intersection of angle AEF and angle DPC is ray ED. My question is how can these two angles intersect if they don't have any points in common? Do they intersect? Where?
Date: 08/26/98 at 23:54:36 From: Doctor Pat Subject: Re: Geometry Todd, They do have points in common, but they didn't use them to name the object. Think for a moment about the line containing points P, Q, R, and S in order. The ray PQ will contain R and S although we do not need to use them to name the ray. In your problem it is clear that since rays EA and EF make up one angle, and the ray ED is the intersection with AEF and DPC, one of EA or EF must be the same as ED. So pick D to be along one of these. D is also on the ray EA. What do we know about P and C? Well, since ray EA, also known as ray ED, is the intersection of both angles, ED must be a subset of one of the two rays that make up DPC, and since it contains D, it would have to be the ray PD, with point C off to the side somewhere. Now the only problem is where to put P. If P is not the same as E then it must be on ray ED or off of it, but if it were located somewhere on the ray ED, the intersection would not contain point E, so it must be that point E lies on the ray PD. Here is a picture: C F / / / / / / P--------------E---------------D-------------A I hope that helps a little. Of course it could be that C is down below or off to the left or someplace, but the other two rays must not intersect or else there would be another point in the intersection. Thanks for sending the question. I had to really think hard to figure that one out. Thanks for the challenge. - Doctor Pat, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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