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Polygons and TrianglesDate: 03/09/99 at 16:42:14 From: Jonathan Randall Subject: Polygons and Triangles I have used loci to prove that isosceles triangles have a greater area than scalene triangles, when a regular n-sided polygon is split up into n triangles, with a set perimeter. But this does not specifically show that regular polygons have greater areas than irregular polygons. Can you help?
Date: 03/11/99 at 12:01:00
From: Doctor Peterson
Subject: Re: Polygons and Triangles
You are on the right track. The approach I have in mind uses what you
have proved, but requires a slight twist in your thinking, more or
less a proof by contradiction.
I would take any non-regular polygon and show that you can find a
larger polygon with the same perimeter. Then the largest polygon with
that perimeter must be regular.
Suppose that there are three consecutive vertices A, B, and C in a
polygon such that AB and BC have different lengths. See if you can
find a point B' for which AB' and B'C are the same length, but their
sum is the same as AB + BC. Then show that the area of triangle AB'C
will be larger than that of ABC. (This is basically what you have told
me already.) If you replace B with B' in the polygon, its perimeter
stays the same but the area is larger.
B'
B +
+ / \
/ \ / \
/ / \ \
/ / \ \
/ / \ \
/ / \ \
/ / \ \
A // \\ C
+ - - - - - - - - - - - - - - - - - +
| \
| \
... ...
This will show that the largest polygon has to have all sides the
same, since a polygon whose sides are not the same is never the
largest.
You will also have to show that the angles in the largest polygon with
a given perimeter are all the same. Try a method similar to what we
just did for the sides. (I have not taken the time to work that part
out.)
- Doctor Peterson, The Math Forum
http://mathforum.org/dr.math/
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