Surface Area of a Sphere
Date: 03/25/99 at 09:03:01 From: Gillian Bravo Subject: Surface area of a sphere How do I calculate the surface area of a sphere? There is a formula, but I can't remember it.
Date: 03/25/99 at 11:32:11 From: Doctor Bruce Subject: Re: Surface area of a sphere Hello Gillian, The surface area of a sphere is 4*Pi*r^2, where r stands for the radius of the sphere, and Pi is the constant approximately equal to 3.14159. The symbol `r^2' means r x r; i.e., you multiply the radius by itself. You might recognize the quantity Pi*r^2 (without the '4') as being the area of a circle of radius r. If you slice the sphere through the center you expose a circular surface which has area Pi*r^2. So, the formula I gave you says that the surface area of a sphere is 4 times the area of a circular cross-section through the center of the sphere. I once saw an experiment with a sphere of styrofoam. Someone sliced it through the center, then took one of the hemispheres and put a pin in the center of the cross-section. Then he wound string around the pin, laying it down smoothly the way you would coil up a garden hose, until the circle was filled up. Then he measured how long a piece of string it took to do that. Then he did the same thing with the *outside* of the sphere, putting a pin exactly in the "north pole" and winding string around it until it covered the surface of the hemisphere. It turned out to take exactly twice as much string to cover the outer surface as it did to cover the flat cross-section. It seems that a hemisphere has twice the area of the cross-section. Since a whole sphere has two hemispheres, its surface area would be 4 times the area of the cross section. Of course, the formula 4*Pi*r^2 is derived mathematically, using principles of calculus. The experiment with string is what we call 'heuristic', meaning it is helpful to our understanding, but it is not a rigorous computation. For more about sphere formulas, you can look at the Dr. Math FAQ: http://mathforum.org/dr.math/faq/formulas/faq.sphere.html Happy surfacing, - Doctor Bruce, The Math Forum http://mathforum.org/dr.math/
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