Surface Area of Pyramids
Date: 05/21/99 at 14:43:28 From: Andy Copley Subject: Surface Area of Pyramid - Slants? Dr. Math, We understand how to find the surface area, but we cannot figure out how to determine the slant. The information given is the height and the base edge.
Date: 05/21/99 at 16:56:42 From: Doctor Peterson Subject: Re: Surface Area of Pyramid - Slants? Hi, Andy. Thanks for your question. I'll assume you are dealing with a right square pyramid; for other bases you can work it out almost the same way. Here's our pyramid, with base edge a and height h: + //|\ ///| \ / // | \ / // | \ / / / | \ / / / | \ / / / | \ / s/ / |h \ / / / | \ / / / | \ / / / | \ +-----/---/-------|-----------\ \ / / | \ \ / / | \ +----/---------+ \ \ / r \ \ / \ +-----------------------------+ a The height of the slanted face, s, is the hypotenuse of a triangle with legs r = a/2 and h. You can use the Pythagorean Theorem to find s, s = sqrt(h^2 + (a/2)^2) and then find the area of each face, as/2. You may notice that if you want the length of the slanted edge for some reason, you can use the Pythagorean Theorem again. If the base were triangular, you would have to find the apothem r by different means. I'll let you handle that if you need to. If you haven't looked at our FAQ on formulas, you'll find the page on pyramids here: http://mathforum.org/dr.math/faq/formulas/faq.pyramid.html This gives formulas for s in the square case. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/
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