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### Locating a Ship Using Three Angles

```
Date: 07/07/99 at 18:19:28
Subject: Geometry Angles

Dr. Math,

The navigator of a ship S saw landmarks in the distance at three
points A, B, and C. Taking sightings from the deck of the ship she
found that angle ASB = 100, angle BSC = 125 and angle CSA = 135. Then
she located the three points A, B and C on a map and used the fact
that an inscribed angle is half the measure of the central angle to
find the exact position of her ship. How did she do it?

I drew an angle ASB and then drew the perpendicular bisectors of each
side to draw a circle with points A, S and B on the circle. Then I
created a point C such that angle BCS was 125 degrees and drew the
perpendicular bisectors of BC and CS to draw a circle with points B,
C, and S in common. Then I did it one last time with the last angle.
All three circles intersected at S, but I do not understand how this
helps me. I never used the inscribed angle theorem and I started with
S already located on my paper. I do not believe this is right. Please
tell me where I went wrong.

Thank you,
```

```
Date: 07/08/99 at 12:10:16
From: Doctor Peterson
Subject: Re: Geometry Angles

Hi, Thaddeus. This is a nice problem. I'll try to give you a hint to
get you started in the right direction.

As you recognized, you can't start with point S and claim to have
found where it is. But you can work backward in another sense to solve
a problem like this.

Let's start by drawing a point S and three rays from it at the
appropriate angles, then pick a point on each ray to be A, B, and C.
That sets things up for us; if we can find a method that doesn't use
point S, but ends up putting a dot where S is, we'll know we've solved
it.

\
\
\ B
+
\
\
\
\
\
\                         A
S+------------------------+-
/
/
/
/
+
/ C
/
/

Now how can we find S? Let's concentrate on points A, B, and S. All we
know about them is that angle ASB is 100 degrees. Suppose they were
all on a circle. Then this would be an inscribed angle, and it would
be half the central angle:

***********
*****           *****
***                     ***
**                           **
*                               *
**                                 **
\   *                    200              *
\  *                                     *
\*B                   O                  *
+-------------------+                   *
*\                    \                 *
*\                     \              *
* \                      \            *
**\                      \         **
*\                       \      *
**100                     \A **
S+**---------------------*+*-----
*****           *****
***********

In fact, if we could find that point O to use for the center of the
circle, then the circle would be the locus of all points S for which
angle ASB = 100 degrees. That's because the central angle, and the arc
intercepted by ASB, are the same no matter where S is on the circle.

Now you just have to figure out how you can locate point O, using only
points A and B and the angle. If you do the same thing for BC and CA,
you'll have drawn three circles that intersect at S. (Actually you'll
only have to draw two of them, unless you want to check the accuracy

- Doctor Peterson, The Math Forum
http://mathforum.org/dr.math/
```
Associated Topics:
High School Euclidean/Plane Geometry
High School Geometry
High School Practical Geometry

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