Sizing a ConnectorDate: 06/01/2001 at 15:09:15 From: Tom Banghart Subject: Overall diameter on any given number of diameters bunched together I have to come up with a specific diameter for anywhere from 2 to 91 diameters that are bunched together. The application is round wires. I am given the number and the diameter of wires that I have to fit into a round connector. The connector is compressed after the wires are bunched together (trying to get them as round as possible). I need the overall diameter so I can size the connector before it is pressed. I know the sum of the diameters is not accurate. Date: 06/01/2001 at 23:10:01 From: Doctor Peterson Subject: Re: Overall diameter on any given number of diameters bunched together Hi, Tom. For small numbers of wires, the answer will depend very much on the number and arrangement of the wires. For only two wires, of course, the bunch will have twice the diameter of one wire - but not much of the connector will be filled. For three wires, they would form an equilateral triangle, and we could figure out the diameter of the largest circle that fits around them. (I get about 2.15 times the diameter of a wire.) Each larger case requires a new calculation, because the best arrangement will be different. For large numbers, we can approximate the diameter, assuming they are fitted together as tightly as possible. If I just imagine an infinite number of circles filling a plane, packed together in a triangular arrangement, I can calculate that the circles will take up pi/(2 sqrt(3)) of the total area, which is about 91%. If I now draw a larger circle (with radius R) that contains N of the small circles (with radius r), the total area of those N small circles should be about 91% of the area of the large circle. This gives me the equation N * pi r^2 pi ---------- = --------- pi R^2 2 sqrt(3) Solving for the ratio R/r, I get R/r = sqrt[N * 2 sqrt(3)/pi] = 1.05 sqrt(N) So I would estimate that the radius of a circle containing N tightly packed circles will be somewhat larger than the square root of N times the radius of each of the small circles. For small numbers, this will be much too small; but for large N it might serve as a good estimate. Let me know whether the large-number approximation is suitable, or you need specifics for a certain range of small N. I may be able to help if you don't need too many cases. - Doctor Peterson, The Math Forum http://mathforum.org/dr.math/ |
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