Carpet ProblemDate: 10/15/2001 at 08:12:08 From: Nathan Pelletier Subject: Carpet Problem 10x10 1x8 = 9x12 You have to carpet a 9x12 room, but when you go the store they only have a 10x10 carpet and a 1x8 piece of carpet. If you add up the number of square units, then 10x10 and 1x8 = 108 and 9x12 = 108, so you know that it can fit. However, you can only make one cut in the carpet (meaning either entering one side of the carpet and exiting any side, or entering one side of the carpet and cutting over yourself). Where would this cut be to make the carpet fit in a 9x12 room.? Date: 10/15/2001 at 14:02:22 From: Doctor Rob Subject: Re: Carpet Problem 10x10 1x8 = 9x12 Thanks for writing to Ask Dr. Math, Nathan! Try this: o---+---+---+---+---+---+---+---+---+---o | | o---+---o + | | | + o---+---o + | | | + o---+---o + | | | + o---+---o + | | | + o---+---+---+---+---+---o + | | | + o---+---o + | | | + o---+---o + | | | + o---+---o + | | | + o---+---o | | o---+---+---+---+---+---+---+---+---+---o Slide the upper right piece two feet right and then one foot down, and see what happens. - Doctor Rob, The Math Forum http://mathforum.org/dr.math/ Date: 10/15/2001 at 14:05:31 From: Doctor Greenie Subject: Re: Carpet Problem 10x10 1x8 = 9x12 Hi, Nathan - I have seen this problem posed many times, and the instructions are virtually never clear. For example, in your presentation of the problem, I don't know what "cutting over yourself" means. Here are a couple of things I think you need in order to have a chance of solving this problem: (1) You can only cut one of the pieces of carpet, giving you a total of three pieces. Putting the two original pieces on top of each other to make the cut is not allowed, nor is folding the piece you cut so that the single cut gives you more than three pieces. (2) You can't solve the problem by making a single straight cut. It has to be some sort of fancy zigzag cut. Note that for the resulting pieces to exactly cover a rectangular floor, the cut will have to consist of segments all at right angles to each other. Those are a couple of hints that might help you find the solution; but I suspect that even with those hints only a tiny fraction of students would be able to do so. (I never figured out the problem for myself - I had to be shown how it is done...) If you don't feel like playing with the problem longer on your own, here is a link to a page in the Dr. Math archives where the solution to your problem is described: Cutting Carpet http://mathforum.org/dr.math/problems/andriano.9.9.96.html - Doctor Greenie, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/