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### Rule of Three

```
Date: 01/23/2002 at 10:08:38
From: Roger Staiger
Subject: Geometry

My grandfather's grandfather's father (born 1811) was a land surveyor
in Southeast Pennsylvania. I am fortunate to have the notebooks he
kept when he was studying to be a surveyor. He created these
handwritten note books in 1828-29 when he was 17 or 18.

The books are interesting in that there were no calculators or slide
rules back then and everything is done by hand - even roots. Most of
the problems are geometry. He makes liberal use of formulas and what
was called back then "The rule of three," but today might be called
simple proportions (A:B::C:?).

There are several problems for which I am unable to replicate the
answer, so I thought I would ask you to assist on one:

How high above the surface of the earth must a person be raised to
see 1/3 (one third) of its surface?

Answer: To the height of the earth's diameter.

He does the problem using "The rule of Three." I can not understand
his logic, replicate his solution, or obtain my own. Can you assist?
Thanks.

Roger Staiger, Scotland, MD
```

```
Date: 01/23/2002 at 12:32:12
From: Doctor Peterson
Subject: Re: Geometry

Hi, Roger. Fascinating story!

You are right that the rule of three refers to simple proportion; it's
incredible to me how recently such a simple process was considered
special enough to have a name, but it goes back to medieval times, I
believe.

I would first ask how to find the area of the portion you can see,
which would be a spherical cap:

http://mathforum.org/dr.math/faq/formulas/faq.sphere.html#spherecap

S = 2 Pi r h

where r is the radius of the earth and h is the height of the cap.
Thus the area is proportional to h.

How is that related to your height d?

P+
|\
| \\
|   \
|    \
d|     \
|      \\
|        \
|         \
|          \\
***********       \
*****     |     *****   \
****          |          ****\
**             h|              **\
*                |Q               *\ R
**-----------------+-----------------**
*                   |             ----  *
*                 r-h|         ----       *
*                    |     ---- r         *
*                     | ----                *
*---------------------+---------------------*
*                     O                     *
*                                         *
*                                         *
*                                       *
**                                   **
*                                 *
**                             **
****                     ****
*****           *****
***********

Comparing similar triangles OPR and ORQ, we find that

r+d    r
--- = ---
r    r-h

Cross-multiplying,

(r+d)(r-h) = r^2

r^2 + dr - hr - dh = r^2

d(r-h) = hr

d = hr/(r-h)

Now, to make the area 1/3 of 4 pi r^2, the area of the earth, h must
be 1/3 of 2r. Plugging this in,

d = (2r/3)r / (r - 2r/3)

= (2r/3)r / (r/3)

= 2r

How does that compare to his solution? I have to assume that the
formula for the spherical cap, or at least the knowledge that the area
is proportional to the height, must have been assumed.

- Doctor Peterson, The Math Forum
http://mathforum.org/dr.math/
```

```
Date: 01/24/2002 at 09:16:13
From: Roger Staiger
Subject: Geometry/Thank you

Thank you for the solution to the problem. I need to study it, but it
seems to be similar to the 1828 solution.

It would appear that the early solution assumed that the area is
proportional to height. This is not an assumption that was obvious to
me until your answer. I do not have the original textbook, only the
handwritten notebook. There is a reference in the notebook to "The
Remainder of Promiscuous Questions, in Bonacastles Mensuration
(sic, I think)."  This may have been his textbook. I believe his
notebook answers were numbered consistent with the text. Someday when
I have extra time, I intend to stop into the Library of Congress
and see if such a book exists.

Thanks again.
Roger Staiger
```
Associated Topics:
High School Euclidean/Plane Geometry
High School Geometry
High School History/Biography

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