An Identity for Solving a Logarithm Problem
Date: 1/25/96 at 16:41:30 From: Anonymous Subject: nlogn = x What is the identity for solving this type of problem... nlog n = (a number) baseX Thanks, Bill
Date: 1/27/96 at 20:49:53 From: Doctor Ken Subject: Re: nlogn = x Hello! There are two things you'll have to use to solve this problem: 1) z log(y) = log(y^z) and then 2) log (y) = z means the same thing as b^z = y base b Good luck! -Doctor Ken, The Math Forum
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