Population of ChinaDate: 05/13/97 at 01:12:40 From: Julie Subject: continuous growth I tried figuring this problem out and I think I got the answer, but I don't know how I got it. Can you please help me and tell me if I am right? Can you also explain how to get the answer? Here's the problem: Given birth rates and death rates, the population of China is assumed to be growing continuously. If the population growth rate is 4.3 percent and the current population of the country is 1.27 billion people, what year will the population reach 2 billion? I got year 2008 and I don't know how. I'd really appreciate it if you could help me. Thanks. Date: 05/13/97 at 05:49:53 From: Doctor Mitteldorf Subject: Re: continuous growth Dear Julie, You can solve this problem by "brute force" by multiplying 1.27 times 1.043, and continuing to multiply the resulting numbers by 1.043 as many times as it takes to get to 2. You find that the number passes 2 after 11 multiplications, so 1997+11 = 2008 is the right answer. Is this what you did? There's a faster way to do this problem, but you need to know about logarithms. Take the log of 2 and subtract the log of 1.27. log(2) = .3010 log(1.27) = .1038 log(2) - log(1.27) = .1972 This tells you that the log has to increase by .1972 as the population increases. But each year, the log of the population increases by: log(1.043) = 0.01828 Now you can just divide .1972 by 0.01828 to get 10.8, so the population will pass 2 billion in 10.8 years. This logarithm method works because multiplying two numbers corresponds to adding their logarithms. -Doctor Mitteldorf, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
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