Algebra 2: Exponents
Date: 01/07/98 at 01:38:49 From: Maryann Subject: Algebra 2 - Exponents I need to find out what "x" is in this problem: x^x^3 = 3. I figured out the answer, but by using solver on my calculator. Now the teacher told us to find out how to solve the equation without using solver or graphing. I have no idea how to do that and what to do to begin.
Date: 01/07/98 at 08:34:32 From: Doctor Mitteldorf Subject: Re: Algebra 2 - Exponents Dear Maryann, In this problem, you happen to be "lucky." If you happen to notice that x^3 = 3 makes the exponent 3 also, so the cube root of 3 solves the equation. You could leave it at that. But it's interesting to think... what if the 3 in the exponent and the 3 on the right had been two different numbers - say 3 and 2. What if your equation was x^(x^3)=2 - how would your solve that There's no integer like 2 or 7 that solves this equation. There's no rational number like 4/3 or 167/125 that solves it either. And I don't think that you can write the solution as the square root or cube root of anything. So it's just a continuing decimal 1.336..., and the best you can do is to find a calculation method that keeps getting you more and more digits of the answer. So... what's a good calculation method? A standard one is called Newton's Method; it works in lots of problems like this one, but it requires calculus, and I think I can offer you one that is less general, but doesn't need calculus. It's called "iteration." You can write the equation as x^(x^3) = 2. Taking the x^3 root of both sides, you can write it as x = 2^(1/x^3). You can use this form of the equation to get better and better guesses for x. Say your first guess is 1.5. Use this number in the right side of the equation, and take 2 to the power 1/(1.5)^3. The answer is x=1.2279... This number is closer to the answer than the 1.5 that you started with. Now do it again: take 2 to the power 1/(1.2279)^3. The answer now is 1.454. Each time you do this, you get a little closer to the answer. You could do it on a calculator or a computer, and after 20 or 30 steps, you'd be as close as you want to be. Even better: notice that the result keeps jumping up and down, estimating too high, then too low, then too high again. When this happens, you can usually do better by averaging each result with the last. For example, if your first x was 1.5 and the next was 1.2279, you'd average those two to give 1.364 as your next guess. Then take 2 to the power 1/(1.364)^3, the answer is 1.307, average this with 1.364 and get 1.335 which is already very close to the right answer. Averaging helps you to get closer with a lot fewer repetitions. Try this method with x^(x^3)=3 instead of =2, and see if you can get closer and closer to the cube root of 3 as an answer. -Doctor Mitteldorf, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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