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Indirect ProofsDate: 09/21/97 at 00:30:35 From: Ashley Subject: Geometry - Indirect Proofs Dear Dr. Math, Can you please explain to me what indirect proofs are, and how to solve this problem, or at least give me a hint? If Clark is a mathemagician, then Lois is his assistant. If Clark is a mathemagician, then everyone at the theater has a good time. If everyone in the theater has a good time, then Lois is not his assistant. Therefore, Clark is not a mathemagician. I really need help with this one. Thanks!
Date: 09/21/97 at 16:35:51
From: Doctor Jodi
Subject: Re: Geometry - Indirect Proofs
Hi there!
I'm not quite sure what you mean by indirect proofs, but I think I can
help you with your puzzle. First of all, let's look at the sentences
that you have:
(1) If Clark is a mathemagician, then Lois is his assistant.
(2) If Clark is a mathemagician, then everyone at the theater
has a good time.
(3) If everyone in the theater has a good time, then Lois is not
his assistant.
(4) Therefore, Clark is not a mathemagician.
Let's focus on the first three sentences for now. Sentences (1), (2),
and (3) are conditional, if-then sentences. We want to find out
whether or not Clark is a mathemagician.
If Clark is a mathemagician:
- Lois is his assistant (from (1))
- everyone at the theater has a good time (from (2))
If Clark is NOT a mathemagican:
(we don't know anything yet)
From (3) we also know that IF everyone in the theater has a good time,
then Lois is not his assistant.
HOLD ON! If Clark is a mathemagician, then everyone has a good time.
So, according to (3), if Clark is a mathemagician, then Lois is not
his assistant. Do you see where we got this? BUT, from (1), we know
that if Clark is a mathemagician, then Lois is his assistant.
So we have a contradiction: Lois both MUST BE (from (1)) and CAN'T BE
(from (2)) Clark's assistant.
But we got this contradiction because we assumed that Clark was a
mathemagician. So he can't be one, as (4) says.
Does this make sense? And since we don't know anything if Clark is not
a mathemagician, there is no contradiction.
Thanks for your question. Please write back if you need more help.
-Doctor Jodi, The Math Forum
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