Date: 03/20/98 at 07:40:23 From: David Maxwell Subject: Logic When the fire alarm went off 6 people in a room each grabbed a coat. When they got outside, they found that no one had his own coat. The coat A had belonged to the man who had seized B's. The owner of the coat grabbed by C held a coat that belonged to the man who was holding D's coat. The man who seized E's coat was NOT the owner of the coat F grabbed. a) Who has A's coat? b) Whose coat does A have?
Date: 03/23/98 at 10:21:17 From: Doctor Sorelle Subject: Re: Logic Dear David, I generally like to think of these types of problems in circles or lines. I take a look at each of the clues and try to see a way to map out what they are telling me. The first clue in this problem says that the coat A now has belongs to an unknown man who is holding B's coat. I can represent that by: A -> __ -> B meaning A has the coat of someone who has B's coat. The next clue is a little more confusing. C grabbed the coat of the man who was holding the coat belonging to the man holding D's coat... hmmm... so in this clue there are two unknown people in the chain, the man whose coat C is holding and the man holding D's coat. The chain I now make looks like this: C -> __ -> __ -> D Then the last clue: F did not grab the coat of the man who has E's coat. I represented that as: This is NOT true: F -> __ -> E Now I try to combine the chains into one long chain or a couple of smaller ones. Maybe the first two chains can go into the big chain: A -> C -> B -> __ -> D -> __ -> A (it's like a circle) That seems to work as far as the first two clues go, but what about the third? Can you see where the E and the F would go? Now do you think that you can answer the questions? Have fun! -Doctor Sorelle, The Math Forum Check out our web site! http://mathforum.org/dr.math/
Date: 03/25/98 at 09:30:31 From: Youngho Cho Subject: Re: Logic Couldn't you "link" the chains in different ways to produce different results? e.g. C -> F -> A -> D -> B -> E -> A Please help. Thanks.
Date: 03/27/98 at 09:29:42 From: Doctor Sorelle Subject: Re: Logic David, Yes, it does seem to me that you could link the chains in different ways to produce different results. I found one other way of linking them: C -> F -> A -> D -> B -> E -> C which is the same as the other one that you found, except instead of having an A at the end of my chain I have a C. You used A twice (oops!). What I think is interesting is that both times the same person is holding A's coat! The two different ways do produce two different answers to the question of whose coat A is holding. But don't worry about it, it's okay to have two different answers to the same question, as long as they both make sense! :-) -Doctor Sorelle, The Math Forum Check out our web site! http://mathforum.org/dr.math/
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