Odd Perfect NumbersDate: 01/23/2001 at 11:12:24 From: chris billingham Subject: Perfect numbers My teacher has set me a question about the odd perfect numbers. I have thought about it, and if there is a odd number, say 999, and you want to see if it is a perfect number, you would need half of the number: 999 / 2 = 499.5 499.5 all the other factors All the other factors must equal 499.5 for it to work. But this can't happen, as a factor has to be a whole number. So does this prove there are no perfect numbers? Date: 01/23/2001 at 15:45:35 From: Doctor Rob Subject: Re: Perfect numbers Thanks for writing to Ask Dr. Math, Chris. Sorry, but this isn't a proof. It isn't even an example, because 2 is not a factor of 999, and neither is 499.5. For n to be a factor of 999, it must be that 999 = n*m, where n and m are both natural numbers. The factors of 999 are 999, 333, 111, 37, 27, 9, 3, and 1. The factors other than 999 add up to 521, which is less than 999, so 999 is deficient, and not perfect. If there is an odd perfect number N, it must have more than 300 decimal digits, and satisfy a large number of complicated conditions. Here are a few: 1. N must leave a remainder of 1 when divided by 12 or a remainder of 9 when divided by 36. 2. It must have at least six different prime divisors. 3. It must have the form p^e*m^2, where p is a prime and both p and e leave a remainder of 1 when divided by 4. 4. If m = q1^a1 * q2^a2 * ... * qn^an, each q a prime number, then not all of the a's can equal 1. If a2 = ... = an = 1, then a1 > 2. If a3 = ... = an = 1, then not both a1 and a2 can equal 2. 5. a1 = a2 = ... = an = 2 is impossible. 6. The set {1+a1, 1+a2, ..., 1+an} cannot have as a common divisor 9, 15, 21, or 33. 7. If e = 5, then ai > 2 for all i's. 8. If N is not divisible by 3, it must have at least 9 different prime divisors. If N is not divisible by 21, it must have at least 11 such divisors. If not divisible by 15, it must have at least 14 different prime divisors, and if not divisible by 105, it must have at least 27 such divisors. 9. If N has exactly r different prime divisors, the smallest of them will be smaller than r+1. Reference: Beiler, Albert H., _Recreations in the Theory of Numbers - The Queen of Mathematics Entertains_ (New York, NY: Dover Publications, Inc., 1964), pp. 12-13. - Doctor Rob, The Math Forum http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2015 The Math Forum
http://mathforum.org/dr.math/