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Product and Sum of Digits = NumberDate: 10/24/2001 at 18:58:17 From: Meghan Jordan Subject: Word problem... How many two-digit numbers exist such that when the products of their digits are added to the sums of their digits, the result is equal to the original two-digit number?
Date: 10/25/2001 at 11:05:19
From: Doctor Ian
Subject: Re: Word problem...
Hi Meghan,
A two digit number looks like
ab
which is just shorthand for
10a + b
where a is between 1 and 9, and b is between 0 and 9.
The product of the digits would be
a*b
The sum of the digits would be
a+b
So if the number is equal to the product of the digits plus the sum of
the digits, then
10a + b = (a*b) + (a+b)
= a*b + a + b
= (b+1)*a + b
Now, this is interesting, because it means that b+1 must be equal to
10. So that certainly narrows things down a bit.
Can you take it from here?
- Doctor Ian, The Math Forum
http://mathforum.org/dr.math/
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