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Summing a Series Like n*(n!)Date: 10/28/2001 at 02:34:37 From: Aberlig Subject: Summing up series like n*(n!) Hello, I was recently reading a book and was wondering how to add up a series whose nth term is n*(n!) where the ! sign indicates factorial, so n! = n*(n-1)* ... 2*1. The series went like 1*1! + 2*2! + 3*3! ... n*n!. Please also show the steps and the method used to solve this problem. Thank you, Aberlig
Date: 10/29/2001 at 08:15:06
From: Doctor Floor
Subject: Re: Summing up series like n*(n!)
Hi, Aberlig,
Thanks for writing.
We will show that 1*1! + 2*2! + ... + n*n! = (n+1)! - 1.
This can be done by mathematical induction.
First we note that 1*1! = 2! - 1, so for n = 1 the formula is correct.
Then suppose that 1*1! + 2*2! + ... + n*n! = (n+1)! - 1. We will show
that then 1*1! + 2*2! + ... + n*n! + (n+1)*(n+1)! = (n+2)! - 1.
Let's go:
1*1! + 2*2! + ... + n*n! + (n+1)*(n+1)! =
(n+1)! - 1 + (n+1)*(n+1)! =
(n+2)*(n+1)! - 1 =
(n+2)! - 1
And we have proved the formula by mathematical induction.
If you have more questions, just write back.
Best regards,
- Doctor Floor, The Math Forum
http://mathforum.org/dr.math/
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